Hi Jon
Thanks for your reply. I read the article but with Oracle, a sequence
and trigger needs to be created for autogenerated primary keys. If I
try the code that you gave me, neither the sequence nor trigger are
created - ie
C:\DjangoTraining\PK>python manage.py sql test
CREATE TABLE "TEST_EMPLOYEE" (
"EMPLOYEE_CODE" NVARCHAR2(10) NULL PRIMARY KEY,
"FIRST_NAME" NVARCHAR2(20) NULL,
"LAST_NAME" NVARCHAR2(20) NULL
)
;
COMMIT;
If I let Django create a primary key, they are:
C:\DjangoTraining\PK>python manage.py sql test
CREATE TABLE "TEST_EMPLOYEE" (
"ID" NUMBER(11) NOT NULL PRIMARY KEY,
"FIRST_NAME" NVARCHAR2(20) NULL,
"LAST_NAME" NVARCHAR2(20) NULL
)
;
CREATE SEQUENCE TEST_EMPLOYEE_SQ;
CREATE OR REPLACE TRIGGER TEST_EMPLOYEE_TR
BEFORE INSERT ON "TEST_EMPLOYEE"
FOR EACH ROW
WHEN (new.id IS NULL)
BEGIN
SELECT TEST_EMPLOYEE_SQ.nextval INTO :new.id FROM dual;
END;
/
COMMIT;
Am I missing something here?
Thanks again
Catriona
On Aug 14, 6:24 pm, "Jon Atkinson" <[EMAIL PROTECTED]> wrote:
> Catriona,
>
> I have very little Oracle experience, but also no reason to think that
> setting a custom primary key would be different from any other
> database backend.
>
> The documentation is
> here:http://www.djangoproject.com/documentation/models/custom_pk/
>
> The primary key is set by using 'primary_key=True' in the model. A
> simple model with a custom primary key:
>
> class Employee(models.Model):
> employee_code = models.CharField(max_length=10, primary_key=True)
> first_name = models.CharField(max_length=20)
> last_name = models.CharField(max_length=20)
>
> I hope this helps.
>
> --Jon
>
> On 8/14/07, Catriona <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > Hello
>
> > I am a beginning Django user and would appreciate help on the
> > following issue.
>
> > How do I specify a custom primary key in my model when using Oracle
> > 10g
>
> > I am using the lastest Django version from svn.
>
> > Thanks for your help
>
> > Catriona- Hide quoted text -
>
> - Show quoted text -
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