Tim,
I think you just got my color search to work (Thank You). Here is the
code:
NO_COLOR = "---------------"
styles = Choice.objects.get(id=h.id).style_set.all()
if ('color' in request.POST) and (request.POST['color'] <> NO_COLOR):
styles = styles.filter(color_cat=request['color'])
for u in styles:
dict[u] = u
////
I did notice that whenever I do a search for just the color 'brown'.
Then the result set will bring back the same style however many
different sizes that are in the style. So if an area rug sells two
choices (2'x3' 39.00, 4'x6' 149.00). Then that style will show up
twice in the result set. Is there anyway better to filter out the
styles that have already been added to the dictionary. My previous
code worked..but not sure it's the best way to do it. Here it is:
num = 0
for a in dict:
if a == j: # 'j' being the name of the style and 'a' is the name of
the style that is already in the dictionary
num = 1
if num == 0:
dict[j] = j
///////////
I know that there is a distinct() method, but I think that only works
over QuerySet's of multiple tables.
Thanks
On Aug 8, 6:56 pm, Tim Chase <[EMAIL PROTECTED]> wrote:
> > Why do I need to do the following:
>
> > if ('price' in request.POST) and (request.POST['price'] <>
> > NOT_PICKED):
>
> > instead of
>
> > if request.POST['price'] <> NOT_PICKED:
>
> In the event that for some reason that field hasn't been sent
> along. This could be some other site using you as a web service,
> this could be your own mistake...in general it's just good
> programming practice to not explode if something goes unexpected.
>
> These could be rewritten as
>
> if request.POST.get('price', NOT_PICKED) <> NOT_PICKED:
>
> if you want to shorten it some.
>
> -tim
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