On Aug 3, 6:37 am, Bram - Smartelectronix <[EMAIL PROTECTED]> wrote: > Hey Everyone, > > does anyone have a good age in years calculation function for usage with > datetime.date that returns the age in nr of years of a person? > > We were using: > > def get_age(self): > now = datetime.today() > birthday = datetime(now.year, self.birthday.month, self.birthday.day) > return now.year - self.birthday.year - (birthday > now) > > But the trouble is that this fails for people whose birthday falls on a > leap-day! ( bday = 1980-02-29 => birthday this year doesn't exist :-) ) > > For now I swaped to: > > try: > birthday = datetime(now.year, self.birthday.month, self.birthday.day) > except ValueError: > birthday = datetime(now.year, self.birthday.month, self.birthday.day-1) > > But that seems such a hack :-)) > > - bram
Not sure how pretty it is, but this seems to work: >>> def age(d, bday): ... return (now.year - bday.year) - \ ... ((now.month < bday.month) or \ ... (now.month == bday.month and now.day < bday.day) and 1 or 0) ... >>> now = datetime.date(2007, 1, 1) >>> bday = datetime.date(1980, 2, 29) >>> age(now, bday) 26 >>> now = datetime.date(2007, 3, 1) >>> age(now, bday) 27 --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
