Hi, I am pretty new to both Python and Django and have a quick and hopefully easy question. Is it possible to create a Model with a link back onto itself?
Check the code below which does not seem to work. class Menu(models.Model): display_text = models.CharField(maxlength=50) url = models.URLField(verify_exists=False) parent_menu_item = models.ForeignKey(Menu) I get the following error when I try to manage.py syncdb Error: Couldn't install apps, because there were errors in one or more models: totalimpact.menu: name 'Menu' is not defined Thanks Christopher --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
