> It doesn't by default. However, have a look
> athttp://www.djangoproject.com/documentation/templates_python/#django-c...to
> see how to enable that. Generic views are given a RequestContext context, so
> providing you enable the correct middleware processors, this will be possible.
You thought about context processors not middleware processors, right?
It messed me for a while but now my code works. So thanks again, you
were very helpful.
Here is my solution (even two solutions)
The problem was: how to get access to 'request' from generic view's
template. I used the following generic view:
django.views.generic.list_detail.object_detail.
1. First solution requires us to modify urls.py
import django.core.context_processors
project_dict = {
'queryset': Project.objects.all(),
'context_processors': [django.core.context_processors.request] #
this is context_processor which enables request for our generic view
}
urlpatterns = patterns('',
(r'^projects/(?P<object_id>\d+)/$',
'django.views.generic.list_detail.object_detail', project_dict),
)
2. Second solution is a global change for all generic views' templates
We must modify settings.py file and add there:
TEMPLATE_CONTEXT_PROCESSORS = (
"django.core.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.request" #this one solves "lack of
request" problem
)
First four context processors here are defaults so I left them
untouched.
> Once you have the "request" variable in your template, you can forget
> about GET or POST. Just access the variable you want as an attribute on
> the "request" (you can do this in Python, too). HttpRequest classes have
> a __getitem__ method that allows you to treat them like a dictionary and
> they will look for the variable in POST first and then GET.
Great! Thanks.
--
Jakub Wisniowski
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