If it's not necessary to have the client *actually* go to the page,
you could so some shady things with httplib [1].
E.g.
import httplib, urllib
params = urllib.urlencode(request.POST)
headers = {"Content-type": "application/x-www-form-urlencoded",
"Referer": "http://google.com"}
conn = httplib.HTTPConnection("funsite.com:80")
conn.request("POST", "/interesting-place", params, headers)
response = conn.getresponse()
if response.status == 200:
data = response.read()
conn.close()
return HttpResponse(data)
conn.close()
raise Http404
This is a very rough sketch of the shadiness you can do.
Cheers,
Mike Axiak
1: http://docs.python.org/lib/module-httplib.html
On May 3, 4:24 pm, "Bob T." <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> I have a situation where I would like a view to do a redirect to a URL
> that is expecting POST (rather than GET) data. GET would be easy, but
> how can I do a POST redirect? The URL I would be redirecting to is not
> under my control, so I can't just change it to use GET data.
>
> Thanks,
> Bob
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