On 4/10/07, Grupo Django <[EMAIL PROTECTED]> wrote:
>
> I know this is not the right place for asking about python, but it's a
> simple question.
> I need to load an object given in a string. Example:
>
> #I have a class called foo
> class foo:
> def Hello():
> return "Hello World"
>
> object = 'foo'
>
> print object.Hello()
You probably don't really want to use the variable name "object",
since that's also the name of Python's base class.
But just to follow your example, these lines (almost) do what you want:
object = foo()
print object.Hello()
Now I'll rewrite it using better Python conventions and correct a small bug:
class Foo(object):
def hello(self):
return "Hello World"
o = Foo()
print o.hello()
Note:
* upper-case class name
* consistent indention (4 spaces)
* lower-case method name.
* method name takes explicit "self" argument, similar to implicit
"this" in other languages
* avoid using built-in names in variables
To see a list of built-ins you should avoid stomping on, try this at
the python prompt:
dir(__builtins__)
To see more about python coding conventions, see PEP 8:
http://www.python.org/dev/peps/pep-0008/
To get a nice overview of Python, see this:
http://docs.python.org/tut/
If you're new to programming, this may be more helpful:
http://www.greenteapress.com/thinkpython/
If you're experienced with programming but new to Python, try this:
http://diveintopython.org
To get more help with Python (not Django) see python-help:
http://mail.python.org/mailman/listinfo/python-help
Welcome to Python.
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