On Tue, 2007-02-27 at 23:30 -0800, Orin wrote:
> Hi,
> the task is to make filter that will check template content for non-
> permitted instructions.
> If I will use the "dumb" way and just try to look for such tags
> directly by comparing strings than I can run across simpe text in my
> template which is not good.
>
> For example, in this template non-permitted instruction is "for".
>
> {% block title %}for my dear woman{% endblock %}
> {% block content %}
> {% for entry in blog_entries %}
> ....
> ....
> {% endfor %}
> {% endblock %}
>
> Please, if anyone know how to solve this problem give me a hint.
Have a look at how tags are implemented in
django/template/defaulttags.py . You will see how it scans for the
closing tag in, say do_block() or do_for() (the parser.parse(...)
calls).
You could use the same approach in your tag (it's probably going to have
to be a tag, rather than a filter, I suspect): after extracting the
"forbidden" word(s) from the tag input, use parser.parse() to search the
template for those words, plus the closing tag of your template (look at
how do_if() searches for "else" or "endif" so that it doesn't find the
"else" from another "if" tag). If you find any such tags, you can then
raise an error.
Hopefully that gives you some ideas to play with.
Regards,
Malcolm
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