oh! Good information. thank you. You can still do most of the movements.
However, with this, it will only be sent to me. Is it not possible to do
something like group_send?
Should I repeat self.send over and over again? I looked at the internal
implementation of group_send, but I couldn't figure out how to do it.
2024年1月15日月曜日 23:11:08 UTC+9 sachin shende:
> By using self.send() after the first group_send, you ensure that the
> message is immediately sent, and then the subsequent messages are sent
> based on time.sleep...
> So before import asyncio ,u can write this:
>
> self.send(text_data=json.dumps({"type": "chat_message", "message":
> "first_chatMessage"}))
>
> On Mon, 15 Jan 2024, 6:57 am Kazuki Nagayama, <k_nag...@dynaxt.co.jp>
> wrote:
>
>>
>> That's exactly what!
>> Do you know where this queue is used?
>> I want to forcibly perform the actual operation.
>>
>> WebSocket is not tied to one request per request, so I want to be able to
>> get 1 request and 2 response.
>> 2024年1月13日土曜日 6:25:31 UTC+9 Ryan Nowakowski:
>>
>>> This is not surprising after looking at the code a bit. It looks like
>>> group_send calls send which puts the message in a queue that gets drained
>>> later during worker.handle.
>>>
>>>
>>> https://github.com/django/channels/blob/b6dc8c127d7bda3f5e5ae205332b1388818540c5/channels/layers.py#L217
>>>
>>>
>>> On January 12, 2024 12:19:45 AM CST, Kazuki Nagayama <
>>> k_nag...@dynaxt.co.jp> wrote:
>>>
>>>> django = 5..0.1
>>>> channels = 4.0.1
>>>>
>>>> I have code like below.
>>>>
>>>> ```python
>>>> class ChatConsumer(AsyncWebsocketConsumer):
>>>> async def receive(self, text_data):
>>>> await self.channel_layer.group_send(
>>>> roomId, {"type": "chat_message", "message":
>>>> "first_chatMessage"}
>>>> )
>>>> import asyncio
>>>> await asyncio.sleep(3)
>>>> await self.channel_layer.group_send(
>>>> roomId, {"type": "chat_message", "message":
>>>> "second_chatMessage"}
>>>> )
>>>> ````
>>>>
>>>> This code expects the first_chatMessage to be sent immediately after
>>>> `receive()` is called, and the second_chatMessage to be sent 3 seconds
>>>> later.
>>>> But what actually happens is that first_chatMessage and
>>>> second_chatMessage are sent at the same time after 3 seconds.
>>>>
>>>> When `receive()` completes execution, it appears that the content
>>>> accumulated in the buffer is sent to the other party.
>>>> Is there a function like `flush()` that forces the buffer to be sent?
>>>>
>>>> thank you.
>>>>
>>>> --
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>>
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