Hello to All!
I need your help figuring out how to solve this issue I'm having while
trying to upload directly to s3 bucket.
I have a function that works perfectly outside of django, I'm trying to
implement it within django so as to be able to upload directly to s3.
1. I do want to first save the file locally
2. Though I'm testing it with one s3 bucket, ultimately the application
will deal with several buckets; I'm not trying to use s3 as a
storage/backend, but rather to use django's UI as a file transfer point
from any end user to his s3 bucket.
This is my scripts (
#function carrying out the upload to s3
def s3_upload_file(file_name, bucket, object_name=None):
if object_name is None:
object_name = file_name
# Upload the file
s3_client = boto3.client('s3')
try:
response = s3_client.upload_file(file_name, bucket, object_name)
except ClientError as e:
logging.error(e)
return False
return True
#function serving to upload the file - linked to UI/django form
#@login_required
def upload_file(request):
if request.method == 'POST':
form = UploadFileForm(request.POST, request.FILES)
if form.is_valid():
file = request.FILES['file'].name
file = str(file)
s3_upload_file(file, 'django-to-s3')#calling the fucntion
# as it takes the uploaded file as input.
return HttpResponseRedirect('/success/url/')
else:
form = UploadFileForm()
return render(request, 'aws/file_upload.html', {'form': form})
I'm using this line: file = str(file), in attempt to cast
request.FILES['file'] as a string, otherwise
s3_upload_file(file, 'django-to-s3') throws an error. Attached are
screenshots of what I get when I run the cmd python manage.py runserver
I will truly appreciate your help. Thanks
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