Hi, BTW it is flask app question. dir structure service config/__init__.py config/config.py src/app.py src/__init__.py
Running the flask app by writing command python src/app.py Question: I want to access config parameter in flask app from config module of config package how can do that. *solutions I tried* write *sys.path.append(''../")* to my src/__init__.py file but its not working please help me write this right way. seems src/__init__.py is not being called. I don't want to change my dir structure and I don't want to write *sys.path.append(''../")* in my app.py file, Thanks in advance -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/5b1e9a97-bede-4454-8b32-9d477fe4d954%40googlegroups.com.