I try to figure out if it possible to implement the next scenario:
garage (app-A)
models
class Vehicle(models.Model)
vin=models.CharField(max_length=50)
...
def import_data(self):
...
# import vehicals
external integration (app-B)
models
class ExtendedVehicle(Vehicle)
external_field=models.CharField(max_length=50)
def import_data(self):
super(ExtendedVehicle, self).import_data()
self.import_external_field()
def import_external_field(self):
...
# import external_field
Something like this.
On Thursday, February 27, 2020 at 7:11:20 PM UTC+2, Jin wrote:
>
> One-time class definition is always good choice, I won't do it like that.
> But can you share the detailed scenario you are gonna implement?
>
> On Fri, Feb 28, 2020 at 1:03 AM Ol P <o...@global-mediator.com
> <javascript:>> wrote:
>
>> I want to extend model-A from app-B without modification of app-A
>> For example, add a field or new methods or override existing.
>>
>> On Thursday, February 27, 2020 at 6:54:37 PM UTC+2, Jin wrote:
>>>
>>> Not sure if I understand the question correctly, but are you trying to
>>> use model-A in app-B?
>>>
>>> On Fri, Feb 28, 2020 at 12:33 AM Ol P <o...@global-mediator.com> wrote:
>>>
>>>> Imagen we have *app-A* and *app-B* with *model-A* and *model-B*
>>>> accordingly.
>>>> And we want to extend *model-A* in *app-B*.
>>>> What should be written in *model-B* to implement it?
>>>>
>>>> In other words, is it possible to implement the same-table extension?
>>>>
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