Try this one :
paginator = Paginator(queryset_list,8) # Show 25 contacts per page
page_request_var = "page"
page = request.GET.get(page_request_var)
try:
queryset = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
queryset = paginator.page(1)
except EmptyPage:
# If page is out of range (e.g. 9999), deliver last page of results.
queryset = paginator.page(paginator.num_pages)
Sent from Mail for Windows 10
From: leb dev
Sent: Wednesday, September 25, 2019 2:32 PM
To: Django users
Subject: where is the error in pagination?
i have a django project and it includes pagination i do not know where is the
error in my code but once i tired to go to the next or previous page it crash
and display the below error :
> can only concatenate str(not ""NoneType) to str
query=request.GET.get("search")
paginator = Paginator(queryset_list, 5)
page_request_var = "page"
print("page_request_var===>",page_request_var)
page = request.GET.get(page_request_var)
print("page===>",page)
queryset = paginator.get_page(page)
print("queryset===>",queryset)
When i print **page** it display None
In the browser it suppose to display **page=2&search=sam**
but instead
it display **/?=2&20search%20=%20sam**
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