Hey there,
I just wanted to clarify that the behavior of including the Meta.ordering
fields in aggregation grouping been around for a while and Django 2.2
deprecates it to deal with the exact type of confusion you experienced here.
Best,
Simon
Le dimanche 2 décembre 2018 08:51:17 UTC-5, Coder Dude a écrit :
>
> Solved It.
> It seems as of django 2.1, we need to add another parameter order_by
>
> *Submission*.*objects*.values('user').annotate(Count('id')).order_by('user')
>
>
> *documentation
> <https://docs.djangoproject.com/en/dev/topics/db/aggregation/#interaction-with-default-ordering-or-order-by>*
>
>
> *Thanks*
>
>
>
>
>
>
> On Sunday, December 2, 2018 at 6:44:21 PM UTC+5:30, Coder Dude wrote:
>>
>> Here are my models:
>> from django.contrib.auth.models import User as DefaultUser
>> class Submission(models.Model):
>> user = models.ForeignKey(to=DefaultUser,
>> on_delete=models.CASCADE
>> )
>> total_score = models.DecimalField()
>>
>>
>> The query that I am trying is :
>>
>> *Submission*.*objects*.values('user').annotate(Count('id'))
>>
>>
>> I want to get the count of Submissions for each user
>>
>> But this returns me set of individual submission with count as 1
>>
>>
>> *Output:*
>>
>> {'user': 1, 'id__count': 1}
>> {'user': 1, 'id__count': 1}
>> {'user': 1, 'id__count': 1}
>> {'user': 1, 'id__count': 1}
>> {'user': 2, 'id__count': 1}
>> {'user': 2, 'id__count': 1}
>> {'user': 3, 'id__count': 1}
>>
>>
>> Whereas the output that I want is:
>>
>> {'user': 1, 'id__count': 4}
>> {'user': 2, 'id__count': 2}
>> {'user': 3, 'id__count': 1}
>>
>>
>> What am I doing wrong?
>>
>> Please help
>>
>>
>>
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