In that answer I assume Jobs are connected anyhow with Persons with a ForeignKey field like so:
*File /appname/models.py:* from django.db import models class Job(models.Model): name = models.CharField(max_length=100) def __str__(self): return self.name class Person(models.Model): name = models.CharField(max_length=100) surname = models.CharField(max_length=100) job = models.ForeignKey(Job, on_delete=models.SET_NULL, null=True, default=None) def __str__(self): return self.name + ' ' + self.surname *File /appname/views.py:* from django.shortcuts import render from django.views.generic.list import ListView from appname.models import Job, Person class JobsWithPersonsView(ListView): queryset = Job.objects.all() template_name = 'jobs_list.html' *File /appname/templates/jobs_list.html:* <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Jobs</title> </head> <body> {% for job in object_list %} {{ job.name }} {% for person in job.person_set.all %} {{ person.name }} {{ person.surname }} {% empty %} Nobody works there. {% endfor %} {% empty %} No jobs. {% endfor %} </body> </html> And others you probably know how to deal with... File /urls.py: from django.contrib import admin from django.urls import path, include urlpatterns = [ path('admin/', admin.site.urls), path('appname/', include('appname.urls')) ] *File /appname/urls.py:* from django.urls import path from appname import views urlpatterns = [ path('jobslist/', views.JobsWithPersonsView.as_view(), name='jobslist') ] *BTW: *Your model names should be in singular form, if you want to be able to use plural forms in some cases, use verbose_name_plural (docs <https://docs.djangoproject.com/en/2.1/ref/models/options/#verbose-name-plural> ). W dniu czwartek, 13 września 2018 05:26:20 UTC+2 użytkownik René L. Hechavarría napisał: > > Hello, > > I have a model, Jobs and Persons, Jobs are listed in ListView, i need to > add a filter (django-filter), if i filter over field in Jobs all work good, > but i need to filter also for Persons. this is and example > > @property > def get_persons(self): > return self.persons_all.all() > > > That allow to add persons to Jobs model in de html. How i filter over > persons in Jobs view? > > Thanks in advance. > > > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at https://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/0c30f699-8dda-43fb-89e2-33e2c8100e4b%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.