Thanks a lot. that worked....
On Tuesday, 17 July 2018 13:29:49 UTC+1, Sainath Bavugi wrote:
>
> I am developing a web app using Django. I have created the table in MySQL
> database and then generated the models.py using inspectdb. I am able to
> fetch details and connect to the database without any issues. But while
> saving the values to the particular table, below error is shown
>
> *Cannot assign "3": "List.id" must be a "Order" instance.*
>
> command used
>
> sav_list = List(id=4, item_name ='name1', item_desc='desc1',
> location='location', reason='rfp', pid=3)
>
> *My models*
>
> class List(models.Model):
> id = models.IntegerField(db_column='ID', primary_key=True) # Field name
> made lowercase.
> item_name = models.CharField(db_column='Item_Name', max_length=255) #
> Field name made lowercase.
> item_desc = models.CharField(db_column='Item_Desc', max_length=300) #
> Field name made lowercase.
> location = models.CharField(db_column='Location', max_length=100,
> blank=True, null=True) # Field name made lowercase.
> reason = models.CharField(db_column='Reason', max_length=100, blank=True,
> null=True) # Field name made lowercase.
> pid = models.ForeignKey('Order', models.DO_NOTHING, db_column='PID') #
> Field name made lowercase.
> class Order(models.Model):
> poid = models.IntegerField(db_column='POID', primary_key=True) # Field
> name made lowercase.
> po = models.CharField(db_column='PO', unique=True, max_length=20) #
> Field name made lowercase.
> quote = models.CharField(db_column='Quote', unique=True, max_length=20)
> # Field name made lowercase.
>
> condition = models.CharField(db_column='Condition', max_length=15) #
> Field name made lowercase.
>
>
> I have tried relate_name for foreign key but still same behaviour. Same
> values can be stored on database without any issues. Only Django throws an
> error.
>
> Please someone help me!!!
>
>
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