On 11/28/06, Jim Fritchman <[EMAIL PROTECTED]> wrote:
>
> The following is SQLObject code and I would like to know how I would do
> the same in Django?
>
> class Order(SQLObject):
> items = MultipleJoin('OrderItem', joinColumn='order_id')
>
> class sqlmeta:
> table = 'orders'
>
> class OrderItem(SQLObject):
> quantity = IntCol(notNone=True)
> price = CurrencyCol(notNone=True)
> total = CurrencyCol(notNone=True)
> order = ForeignKey('Order')
> product = ForeignKey('Product')
>
>
> The key being the list of order items in the Order class?
First, some housekeeping; The Django-Developers list is for discussing
internal Django development, not answering user questions. Cross
posting to both lists won't increate your chance of getting your
question answered, as all the developers subscribe to the User list as
well.
Second - your question:
I presume the crux of your question is the forward reference of the
Order model. Django allows you to forward reference any model class by
using a string containing the model name. This only works for models
that are defined in the same models.py file, but it does allow you to
work around dependency issues like the one you have. So, you are
looking for something like:
class Order(Model):
items = ManyToManyField('OrderItem')
class OrderItem(Model):
quantity = IntegerField()
order = ForeignKey(Order)
Note that the ManyToManyField on Order uses a String, whereas the
ForeignKey on Order uses the class name.
Yours,
Russ Magee %-)
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