[EMAIL PROTECTED] wrote: > But here's a question... why are you trying to put this object into a > string? Seems like you'd be better off just keeping it an object. > Perhaps you'd be better off with a simple > test = document.getElementById('id_embeddedvideo.0.type'); or, if you > needed to do something with it, maybe something like > test.cloneNode(true) > > Just a thought. It seems to me that at BEST, trying to put it into a > string is going to be fragile. > > > The idea is to spit out more fields dynamically (I just increment the .0. part each time). It worked great for other stuff. Example:
var next_file_no = 1; function getFileField(){ var orig = '<p><label>Description</label>{{ form.fileattachment.0.description }}<label>File</label>{{ form.fileattachment.0.image }}{{ form.fileattachment.0.image_file }}</p>'; var filefields = document.getElementById('filefields'); orig = orig.replace(/\.0\./g,'.' + next_file_no + '.'); next_file_no += 1; filefields.innerHTML += orig; } Your idea is a little more work but I think I'll attempt that rather than creating a filter. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---