Hey everybody,
thank you very much for your answers. I think I have already learned a lot
from you! Well - there is quite a difference between stepping through a
tutorial and trying to do something on my own. Regarding Mikes question
whether a step of a recipe should be a sub-recipe. Well, as far as I know
hierarchical relationships are hard to model in relational databases;
that's why I kept my hands off! My decision to create a recipe app has a
simple reason: I read some comparisons between django and ruby on rails and
I decided to go for django since it seems to leave more freedom. I found a
RoR tutorial on creating a recipe app some time ago and I am trying to do
the same thing in django now.
Concerning my model - this is how it looks like:
from __future__ import unicode_literals
from django.db import models
class Unit(models.Model):
abbreveation = models.CharField(max_length=5, primary_key=True)
description = models.CharField(max_length=50)
def __str__(self):
return "%s (%s)" % (self.description, self.abbreveation)
class Ingredient(models.Model):
name = models.CharField(max_length=255)
def __str__(self):
return self.name
class Step(models.Model):
name = models.CharField(max_length=255, blank=True)
recipe = models.ForeignKey('Recipe', related_name='steps', on_delete=
models.CASCADE, null=True)
description = models.TextField()
ingredient = models.ManyToManyField(Ingredient, through='StepIngredient'
)
def __str__(self):
if (self.name == ''):
return "Step %d" % self.id
else:
return "Step %d (%s)" % (self.id, self.name)
# additional information for many to many relationship between schritt and
zutat
class StepIngredient(models.Model):
class Meta:
unique_together = (('step', 'ingredient'),)
step = models.ForeignKey(Step, null=True)
ingredient = models.ForeignKey(Ingredient, null=True)
amount = models.DecimalField(max_digits=7, decimal_places=3)
unit = models.ForeignKey(Unit, null=True)
def __str__(self):
return "%d %s %s" % (self.amount, self.unit.abbreveation, self.
ingredient)
class Recipe(models.Model):
name = models.CharField(max_length=255)
# file will be uploaded to MEDIA_ROOT/images
# TODO: Upload works but link fails. Maybe sth. wrong with MEDIA_URL???
photo = models.ImageField(upload_to='images/', null=True)
portionen = models.IntegerField(default=2)
def __str__(self):
return self.name
Thank you James for pointing me at how to do my queries with django; I can
finally list my steps using:
{% for step in recipe.steps.all %}
within my template. However, given the model above I am still not sure how
to access a single steps ingredients ... any ideas or suggestions on my
current model?
Thanks, Simon
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