Hi Peter, Thank you -- that's perfect!
On Monday, February 1, 2016 at 6:49:31 AM UTC, Peter of the Norse wrote: > > I hope you forgive me skipping all of that getattr nonsense. > > others = Studio.objects.filter(studio_group__in = > choice.studio_group_set.all()).exclude(pk=choice.pk) > > On Jan 28, 2016, at 2:16 AM, dave.l <[email protected] <javascript:>> > wrote: > > Hi, > > I am happy with my models, and I'm fine inserting data, what I would like > help with is retrieval. > > given a single instance of a Studio() I can get > studio.studiogroup_set.all() which I can then iterate to find the > individual studios and build my resulting list ensuring no duplicates and > not 'studio' itself. All this is working in Python: > > choice = self.get_object() > others = [] > for set in getattr(choice, "%s_set" % choice.groupname.lower()).all(): > for other in getattr(set, choice.view_name()).exclude(pk=choice.pk): > if other not in others: > others.append(other) > for other in others: > print other > > but this doesn't seem very elegant and I'm wondering if there's a more > 'django' way of doing this. > > On Wednesday, January 27, 2016 at 8:36:26 PM UTC, Xristos Xristoou wrote: >> >> your code is correct,where are the problem ?in the admin first add Studio >> and sfter this select on the field studio from class studiogroup one or >> more entries from the class studio so simple, >> >> christos >> >> Τη Τετάρτη, 27 Ιανουαρίου 2016 - 5:50:21 μ.μ. UTC+2, ο χρήστης dave.l >> έγραψε: >>> >>> Hi, >>> >>> I have recently returned to a Django project after a few years and I'm a >>> little rusty on ManyToMany fields. >>> >>> Here's my very simple models: >>> >>> >>> class Studio(models.Model): >>> name = models.CharField(max_length=255, unique=True) >>> >>> class StudioGroup(models.Model): >>> description = models.CharField(max_length=255, unique=True) >>> studio = models.ManyToManyField(Studio) >>> >>> >>> So a bunch of Studio(), which can be in multiple StudioGroups() >>> >>> Given a single instance of a Studio(), I would like a single list of all >>> other studios in all other groups. >>> >>> so if Group1 is A,B,C and Group2 is A,D,E >>> >>> I would like to return B,C,D,E for A. >>> >>> My current solution is entirely in Python (which works), but I'd like a >>> more Django-esque solultion of possible! >>> >>> Thank you, >>> >>> > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected] <javascript:>. > To post to this group, send email to [email protected] > <javascript:>. > Visit this group at https://groups.google.com/group/django-users. > To view this discussion on the web visit > https://groups.google.com/d/msgid/django-users/7512817d-d348-48b2-abf1-f3f584650cce%40googlegroups.com > > <https://groups.google.com/d/msgid/django-users/7512817d-d348-48b2-abf1-f3f584650cce%40googlegroups.com?utm_medium=email&utm_source=footer> > . > For more options, visit https://groups.google.com/d/optout. > > > Peter of the Norse > [email protected] <javascript:> > > > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/91e9b116-0edc-41e8-b136-4c35873085bc%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
