Hi all,
I'm working on an application where we want the following to happen:
1. The administrators upload zip archives containing web content (whole
static websites) through admin interface
2. The archive is unzipped in the background to a random directory
3. The static content is served at a url that looks like
http://<host>/site/<pk>/,
with the index.html at the root, all the paths to css and js files, etc.
I know how to configure the route, but I was wondering what to put in the
view. I have tried with STATIC_{ROOT,URL} and MEDIA_{ROOT,URL} but I feel
it's not the right way.
In summary : is there a way to put something like `return
serve_this_static_directory()` in the view? or is there any workaround
there?
Thanks for your answers
Yann
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to django-users+unsubscr...@googlegroups.com.
To post to this group, send email to django-users@googlegroups.com.
Visit this group at http://groups.google.com/group/django-users.
To view this discussion on the web visit
https://groups.google.com/d/msgid/django-users/CAHDVCz73WP6MAC2VqYGkDYRw-vJCkd2fJXRUoZKyybrrjPAt4Q%40mail.gmail.com.
For more options, visit https://groups.google.com/d/optout.
