You can try to put a db_index=True in markid field.
https://docs.djangoproject.com/en/1.7/ref/models/fields/#db-index
On Fri, Jan 23, 2015 at 9:59 AM, Jani Tiainen <rede...@gmail.com> wrote:
> On Fri, 23 Jan 2015 03:38:19 -0800 (PST)
> Joris Benschop <joris.bensc...@gmail.com> wrote:
>
> > And to keep replying to myself:
> >
> > This one is slow:
> > x=Marker.objects.raw("SELECT * from PROD_SCHEMA.MARKER WHERE MARKID=
> > %s",[u'TO1'])
> > print x[0]
> >
> > This one is fast:
> > y=Marker.objects.raw("SELECT * from PROD_SCHEMA.MARKER WHERE MARKID=
> 'TO1'")
> > print y[0]
> >
> > If I copy the table and make the MARKID field in NVARCHAR2(20), then it
> > uses the index properly on both counts
> >
> > So... so do I make django use ascii? is there a field type?
>
> You could try explicit cast to VARCHAR2, not sure does that help at all:
>
> x=Marker.objects.raw("SELECT * from PROD_SCHEMA.MARKER WHERE
> MARKID=CAST(%s AS VARCHAR2)",[u'TO1'])
>
>
> --
> Jani Tiainen
>
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