Collin thank so much really help me!
Cheers
On Sat, Oct 4, 2014 at 11:09 AM, Collin Anderson <cmawebs...@gmail.com>
wrote:
> If you change how your dictionary is formatted, it can be much easier:
> dicc_one = {
> 'string1': {'fieldsFK__total_one__gt': 0},
> 'string2': {'fieldsFK__total_two__gt': 0},
> 'string3': {'fieldsFK__total_three__gt': 0},
> 'string4': {'fieldsFK__total_four__gt': 0},
> }
> results = {}
> for k, v in dicc_one.items():
> results[k] = Model.objects.filter(**v).count()
>
> Otherwise, you'll need to call v.split('=') to split the fields from the
> values.
>
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