It must be more simple than the nothingness that searching google is showing me... how can I to get back to the last page (say page 2: http://127.0.0.1:8000/articlelist/2, which works) in a ListView after an UpdateView.
I can go to a random page - 10 in the below UpdateView - but how do I capture the referring ListView's current page and then feed that back in get_success_url after the update? class ArticleEditView(UpdateView): model = Article template_name = 'edit_template.html' form_class = ArticleForm def get_success_url(self): return reverse('editor_listview', kwargs={'page': 10}) Thank you -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users. To view this discussion on the web visit https://groups.google.com/d/msgid/django-users/646c8295-a5c5-42b4-b3a9-e9a477c1341b%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.