Very helpful, thanks Mike!
On Sunday, March 16, 2014 7:34:11 PM UTC-4, Mike Dewhirst wrote:
>
> On 17/03/2014 9:59am, Gene Coetzee wrote:
> > Hi There!
> >
> > Starting out with Django, and was looking for a bit of guidance. I am
> > trying to establish a Organizational structure for employee/supervisor
> > type relationships. Since each of these individuals will be a user, I am
> > extending trying to also take advantage of django's built-in
> > contrib.auth package.
> >
> > In Short, employees report to supervisors, and in turn supervisors in
> > themselves can report to their respective supervisors... I developed the
> > following models, but was curious if there might be a better way to do
> this:
>
> There will be a few different opinions on this ... here's mine:
>
> class Employee(models.Model):
> user = models.ForeignKey(User)
> def __unicode__(self):
> return self.user.username
>
> class Relationship(models.Model):
> boss = models.ForeignKey(Employee)
> worker = models.ForeignKey(Employee)
> relationship_type = models.CharField(max_size=32)
> def __unicode__(self):
> return "{0} {1} {2}".format(boss, relationship_type, worker)
>
> I just typed this without testing and I think you would need to read up
> on 'related_name' and use null=True here and there to get it working.
>
> I would choose this approach to get some flexibility with multiple
> relationships between employees. Supervisors get supervised too. Also, I
> might choose different field names than "boss" and "worker" if I was
> doing this for myself.
>
> Mike
>
> >
> > class Supervisor(models.Model):
> > supervisor = models.OneToOneField(User)
> > def __unicode__(self):
> > return self.supervisor.username
> >
> > class Employee(models.Model):
> > employee = models.OneToOneField(User)
> > supervisor = models.ForeignKey(Supervisor)
> > def __unicode__(self):
> > return self.employee.username
> >
> > Thank you!
> >
> >
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