I assumed the OP wanted to get *all* instances of Item even if they don't have any liked status equals to 'L'.
The query you provided will filter out instances of Item with `itemlikestatus__count < 1` instead of returning an annotated value of 0. Le mercredi 25 septembre 2013 04:41:37 UTC-4, Daniel Roseman a écrit : > > On Tuesday, 24 September 2013 21:58:44 UTC+1, Simon Charette wrote: > >> Unfortunately the Django ORM's doesn't support conditionnal >> aggregates<https://code.djangoproject.com/ticket/11305> >> . >> > > This is true, but completely irrelevant to the OP's question, which > doesn't require them. The documentation gives an example which AFAICT is > exactly what the OP wants, at > https://docs.djangoproject.com/en/1.5/topics/db/aggregation/#order-of-annotate-and-filter-clauses. > > Translating it into the relevant models: > > items_by_popularity = > Item.objects.all().filter(itemlikestatus__liked_status='L').annotate(Count('itemlikestatus')).order_by('-itemlikestatus__count')[:number_requested] > > -- > DR. > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users. For more options, visit https://groups.google.com/groups/opt_out.
