Dear All, In my view I create the following dictionary of lists from a queryset
#view.py queryset = MyModel.objects.filter(owner=user, dashboard=tab).order_by('position') my_dict = collections.defaultdict(lambda: collections.defaultdict(list)) for obj in queryset: my_dict[int(obj.position.split('-')[0])][int(obj.position.split('-')[2])].append(obj)return Response({'queryset': dict(my_dict)}, template_name='dashboard/_maps_tab.html') Position field is a charFiled following the format: X-X-X-X used the create the my_dict my_dict is --[1] #group----[1] #col 1------ object1.1.1 #group.col.pk------ object1.1.2------ object1.1.3----[2] #col 2------ object1.2.4----[3] #col3------ object1.3.5------ object1.3.6 --[2] #group----[1] #col 1------object2.1.7 #group.col.pk --[3] #group----[1] #col1------ object3.1.8 #group.col.pk----[2] #col2------object3.2.9------object3.2.10 In my template I tried: {% for key, groups in queryset.iteritems %} groups = {{ groups }} <br> {% for group_key, cols in groups.iteritems %} cols = {{ group_key }} <br> {% for objs in cols %} {# rest of the code #} But only the first loop is evaluated groups = (1, defaultdict(<type 'list'>, {1: [<Obj: Obj 1 by daviddd>, <Obj: Obj 2 by daviddd>, <Obj: Obj3 by daviddd>], 2: [<Obj: Obj 4 by daviddd>], 3: [<Obj: Obj 5 by daviddd>, <Obj: Obj 6 by daviddd>, <Obj: Obj 7 by daviddd>]})) groups = (2, defaultdict(<type 'list'>, {1: [<Obj: Obj 7.7 by daviddd>]})) groups = (3, defaultdict(<type 'list'>, {1: [<Obj: Obj 7.8 by daviddd>]})) (Linked question: http://stackoverflow.com/questions/18406126/django-template-loop-collections-defaultdictlambda-collections-defaultdictlis ) I'm not able to spot the error. Thanks D -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users. For more options, visit https://groups.google.com/groups/opt_out.