Thank you.
But I want to fix it like this, because the time of "do something" is not
long.
#######################################
from django.http import HttpResponseimport datetimedef
current_datetime(request):
now = datetime.datetime.now()
if now == 2013:
html = "<html><body>It is now %s.</body></html>" % now
return HttpResponse(html)
else:
# giva a response first
urllib.urlopen(message)
# do something
print 'not 2013'
sys.exit(0)
#######################################
2013/6/25 Hector Armando Vela Santos <vello...@gmail.com>
> You can use Celery for that, I've done something similar, just with a CSV
> instead of a XML, check this
> http://docs.celeryproject.org/en/latest/django/first-steps-with-django.html
>
> once installed and configured, its as simple as:
>
> from celery import task
>
> if (the xml format is ERROR) == True:
> return HttpResponse(<html><body>ERROR FORMAT</body></html>")
> else:
> do_something.delay(the_xml_file)
> return HttpResponse(<html><body>RIGHT FORMAT</body></html>")
> #I must give a response first, And do other thing. Because the spend
> time of do_something() may be long.
>
> @task(ignore_result=True)
> def do_something(xml):
> #do something time consuming
>
>
> and the do_something function will be called in second plane, and the user
> will get an instant response, even if the parsing file process takes half
> an hour
>
>
> On Tuesday, June 25, 2013 8:32:59 AM UTC-5, lx wrote:
>
>> Thank you.
>>
>> The real demand is:
>>
>> 1.
>> receive the xml file from client.
>>
>> 2.
>> if (the xml format is ERROR) == True:
>> return HttpResponse(<html><body>ERROR FORMAT</body></html>")
>> else:
>> return HttpResponse(<html><body>RIGHT FORMAT</body></html>")
>> #I must give a response first, And do other thing. Because the spend
>> time of do_something() may be long.
>> do_something(the xml file)
>>
>>
>>
>>
>>
>>
>> 2013/6/25 Sandro Dutra <hex...@gmail.com>
>>
>>> The question is: What you're trying to do?
>>>
>>> 1. You can do any other process before the return line, the return will
>>> be the same... for example:
>>>
>>> from django.http import HttpResponse
>>> from datetime import datetime
>>> def current_datetime(request):
>>> now = datetime.now()
>>> html = "<html><body>It is now %s.</body></html>" % now
>>> year = now.year()
>>> return HttpResponse(html)
>>>
>>>
>>> 2. You can use a conditional to have multiple returns:
>>> from django.http import HttpResponse
>>> from datetime import datetime
>>> def current_datetime(request):
>>> now = datetime.now()
>>> html = "<html><body>It is now %s.</body></html>" % now
>>> year = now.year()
>>> if year == 2013:
>>> return HttpResponse(html)
>>> else:
>>> return HttpResponse(<html><body>Sorry it's not
>>> 2013.</body></html>")
>>>
>>>
>>> 2013/6/25 Timster <timsha...@gmail.com>
>>>
>>>> You cannot do something after the "return" line. This is Python
>>>> functionality. When you return, the function exits and does not process
>>>> anything else.
>>>>
>>>> What exactly are you trying to do? There is probably another way to
>>>> accomplish it.
>>>>
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>>>>
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>>
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