I needed to pass an instance dictionary, but now I am having a problem with
my models?
http://stackoverflow.com/questions/15684557/setting-choices-and-forms-at-runtime-for-a-form-wizard
On Wednesday, April 3, 2013 11:06:57 AM UTC-4, Nick D wrote:
>
> I see; I didn't understand the flow at first.
>
> Is this line wrong "quiz = Quiz.objects.get(id=quiz_id)"?
>
> I don't think Django names the pk "id" by default. Maybe it should be:
>
> quiz = Quiz.objects.get(pk=quiz_id)
>
> On Monday, April 1, 2013 7:17:13 AM UTC-7, Cody Scott wrote:
>
>> I am trying to make a simple quiz app.
>>
>> I am trying to go to the URL /quiz/<quiz_id> and using the quiz_id which
>> has a list of questions associated with the quiz id and create a list of
>> forms to use in the model form.
>>
>> In the urls.py file I know you can pass a list of forms to be used, but I
>> need to create the list of forms at runtime.
>>
>> I have tried passing the return value of a function as parameter but
>> can't figure out the syntax.
>>
>> (r'^(?P<quiz_id>\d+)', QuizWizard.as_view(get_form_list)),
>> the function get_form_list has no length
>>
>> (r'^(?P<quiz_id>\d+)', QuizWizard.as_view(get_form_list(quiz_id))),
>> Quiz_id is unknown.
>>
>>
>> So I create a view and I create the form list inside the view and then call
>> QuizWizard.as_view
>>
>>
>> #views.pyclass QuizWizard(SessionWizardView):
>> def __init__(self, **kwargs):
>> self.form_list = kwargs.pop('form_list')
>> return super(QuizWizard, self).__init__(**kwargs)
>>
>> def done(self, **kwargs):
>> return render_to_response('done.html', {
>> 'form_data':[form.cleaned_data for form in self.form_list],
>> })
>> def get_form_list(request, quiz_id):
>> quiz = Quiz.objects.get(id=quiz_id)
>>
>> question_forms = []
>>
>> for question in quiz.questions.all():
>> choices = []
>> for choice in question.choices.all():
>> choices.append(choice)
>> f = QuestionForm(instance=question)
>> question_forms.append(f)
>>
>> #quiz_wizard = QuizWizard()
>> return QuizWizard.as_view(form_list=question_forms)(request)
>>
>>
>> But I am getting the error
>>
>> issubclass() arg 1 must be a class
>>
>>
>>
>> My issue is syntax either way I can't figure out how to call the
>> QuizWizard.as_view(). Here are related files:
>>
>>
>> #forms.py
>>
>> class QuestionForm(forms.ModelForm):
>> class Meta:
>> model = Question
>>
>>
>> #urls.py
>>
>> urlpatterns = patterns ('',
>> url(r'^(?P<quiz_id>\d+)', 'quiz.views.get_form_list'),)
>>
>>
>> #models.py
>>
>> class Choice(models.Model):
>> choice = models.CharField(max_length=64)
>> def __unicode__(self):
>> return self.choice
>>
>> #create a multiple choice quiz to start
>> class Question(models.Model):
>> question = models.CharField(max_length=64)
>> answer = models.CharField(max_length=64)
>> choices = models.ManyToManyField(Choice)
>> module = models.CharField(max_length=64)
>>
>> def __unicode__(self):
>> return self.question
>>
>> class Quiz(models.Model):
>> name = models.CharField(max_length=64)
>> questions = models.ManyToManyField(Question)
>>
>> def __unicode__(self):
>> return self.name
>>
>>
>> Full Traceback: http://bpaste.net/show/0YNrLYJSdjdJ7Hea5q1c/
>>
>>
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