Thanks Brad,
I got it working.
@register.filter(name='price')
def price(model, user):
u = UserGroup.objects.get(user_id=user.id)
level = u.price_level
if level == 'B':
return model.price_b
if level == 'C':
return model.price_c
if level == 'D':
return model.price_d
if level == 'E':
return model.price_e
return model.price_a
{{ row|price:request.user }}
On Monday, February 11, 2013 10:54:53 AM UTC-5, Brad Pitcher wrote:
>
> Sounds like you are maybe calling a user method from a template? You
> will probably want to create a custom tag or filter:
> https://docs.djangoproject.com/en/1.4/howto/custom-template-tags/
>
> A filter would look like this:
> {{ my_model_item|price:request.user }}
>
> And the filter itself something like this:
>
> def price(my_model_item, user):
> """Returns the price for the user"""
> # Logic to evaluate the price could be here on in a
> # model method, but if it's in the model method you
> # will need to pass the user as a parameter to that
> # method.
> return evaluated_price
>
> On Mon, 2013-02-11 at 07:05 -0800, frocco wrote:
> > What I am trying to do, is I have four price fields in my model and
> > need to return just one based on current user logged in.
> >
> >
> > price_a
> > price_b
> > price_c
> > price_d
> >
> >
> > I want to always return a field named price, based on one of those
> > fields.
> >
> > On Monday, February 11, 2013 9:51:47 AM UTC-5, frocco wrote:
> > Ok, but is request available in models.py?
> >
> >
> > On Monday, February 11, 2013 9:49:47 AM UTC-5, sandy wrote:
> > On Mon, Feb 11, 2013 at 7:42 PM, frocco
> > <far...@gmail.com> wrote:
> > > Hello,
> > >
> > > I have some logic I want to put in a model, but it
> > requires know the current
> > > user logged in.
> > > Is there a way to get this?
> > >
> > This gets the current logged in user :
> >
> > current_user = request.user
> >
> > --
> > Sandeep Kaur
> > E-Mail: mkaur...@gmail.com
> > Blog: sandymadaan.wordpress.com
> >
> > --
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