(Reposted since my thread was hijacked...)
I have a "legacy database" filled with data for many customer's
website content.
In the admin I always want to filter the queries so that only the
current customer's inventory, categories and subcategories are
viewable. Can this be done with the "sites" framework? Do I need to
hack the CurrentSiteManager class? I am not sure how the
settings.SITE_ID corresponds to my own "keyfgallid" foreign key, so I
just made them the same value.
Here is my model:
from django.db import models
from django.contrib.sites.models import Site
from django.contrib.sites.managers import CurrentSiteManager
from galleryhosting import settings
class Inventory(models.Model):
keypid = models.IntegerField(primary_key=True)
keyfgallid = models.ForeignKey(Gallery,db_column='keyfgallid')
sku = models.CharField(maxlength=45)
name = models.CharField(maxlength=360)
artist = models.CharField(blank=True, maxlength=450)
description = models.TextField()
date_info = models.CharField(maxlength=300)
keyfcategoryid =
models.ForeignKey(Category,db_column='keyfcategoryid')
keyfsubcategoryid = models.ForeignKey(Subcategory,
db_column='keyfsubcategoryid')
h = models.CharField(maxlength=120)
w = models.CharField(maxlength=120)
d = models.CharField(maxlength=120)
site = models.ForeignKey(Site)
#Site Stuff
site = models.ForeignKey(Gallery,db_column='keyfgallid',
blank=True, default=settings.SITE_ID,
related_name='Gallery')
objects = models.Manager()
on_site = CurrentSiteManager(field_name='keyfgallid')
def __str__(self):
return "%s / %s / %s" %
(self.sku,self.name,self.keyfcategoryid,)
class Meta:
db_table = 'inventory'
class Admin:
pass
best,
david
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