Hey guys,
I was wondering if there is a way of making a field null vs not-null filter without coding it yourself? I tried: list_filter = (('field_which_is_foreign_key', BooleanFieldListFilter),) In the end I wrote this little one: class MyFieldFilter(SimpleListFilter): title = _(' field_which_is_foreign_key ') parameter_name = ' field_which_is_foreign_key _n' def lookups(self, request, model_admin): return ( ('T', _('Null')), ('F', _('Not Null')), ) def queryset(self, request, queryset): if self.value() == 'T': return queryset.filter( field_which_is_foreign_key=None) if self.value() == 'F': return queryset.exclude( field_which_is_foreign_key =None) But that's not very generic, I might need this for more fields! Any way to do it with a bool filter? - bram -- http://www.samplesumo.com http://www.freesound.org http://www.smartelectronix.com http://www.musicdsp.org office: +32 (0) 9 335 59 25 mobile: +32 (0) 484 154 730 -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.