On 9/5/06, primitive <[EMAIL PROTECTED]
> wrote:
Ok; so you have a GET request string 'id=1&fk_client_id=2', and you want to compose a query from it.
You will be hitting against two problems:
1) The 'value' for each key in a QueryDict will be a list
2) The values in the list will be strings, not integers, etc.
A simple version without using QueryDict:
get_str = 'id=1&fk_client_id=2'
raw_query = [part.split('=') for part in get_str.split('&')]
query = dict([(k, int(v)) for k,v in raw_query.items()])
Ticket.objects.filter(**query)
A similar approach will also work with QueryDict (and avoids the need to use split) - you just need to compensate for the list in the return value of qdict.iteritems().
This approach is a little fragile, as it assumes that the 'value' is always an integer. However, you could do some funky stuff with a dict to select an appropriate str->value function:
transform = {'id': int, 'fk_client_id': int, 'name':str}
query = dict([(k, transform[k](v)) for k,v in raw_query.items()])
This will use int() to transform id and fk_client_id, but will allow name to pass through as a string.
Hope this helps,
Yours,
Russ Magee %-)
example code
qdict = QueryDict('id=1&fk_client_id=2')
queryset = Ticket.objects
Ok; so you have a GET request string 'id=1&fk_client_id=2', and you want to compose a query from it.
You will be hitting against two problems:
1) The 'value' for each key in a QueryDict will be a list
2) The values in the list will be strings, not integers, etc.
A simple version without using QueryDict:
get_str = 'id=1&fk_client_id=2'
raw_query = [part.split('=') for part in get_str.split('&')]
query = dict([(k, int(v)) for k,v in raw_query.items()])
Ticket.objects.filter(**query)
A similar approach will also work with QueryDict (and avoids the need to use split) - you just need to compensate for the list in the return value of qdict.iteritems().
This approach is a little fragile, as it assumes that the 'value' is always an integer. However, you could do some funky stuff with a dict to select an appropriate str->value function:
transform = {'id': int, 'fk_client_id': int, 'name':str}
query = dict([(k, transform[k](v)) for k,v in raw_query.items()])
This will use int() to transform id and fk_client_id, but will allow name to pass through as a string.
Hope this helps,
Yours,
Russ Magee %-)
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