Hi as you can see here at http://docs.python.org/tutorial/errors.html in 8.3 handling exceptions theres a piece of code that works as you want.
for example try this: try: int("a") except Exception as e: #The key is using "as" and the variable name you like for retrieving the exception because if you dont you will only get #"Exception type" type print type(e) #This will give de exception type. In this case #<type 'exceptions.ValueError>' print e #This will print you the message exception. #invalid literal for int() with base 10: 'a' print e.message #This would give you the string message #invalid literal for int() with base 10: 'a' I hope this can help you, please forgive me for my grammar im mexican. On 14 mayo, 18:29, LJ <ljayad...@gmail.com> wrote: > I am trying to add exception handling to my application. > I have been reading the documentation on Django > Exceptions:https://docs.djangoproject.com/en/dev/ref/exceptions/ > I also found the list of Exceptions (both Django and Python). > But for testing purposes, I need a way to handle all exceptions and to > log the exception types: > > try: > addresses = Address.objects.all() > except Exception: > logger.debug(Exception.Type) > > How do I catch all types of exceptions? And, how do I get the > exception type? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.