Hello, I use postgresql 9.1 with postgresql_psycopg2 on debian (actually this also happens on my mac). I recently moved to django 1.4 and I got this error while creating a simple object : o = Object() o.fieldA = .. .... o.save() Traceback (most recent call last): File "<console>", line 1, in <module> File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/models/base.py", line 463, in save self.save_base(using=using, force_insert=force_insert, force_update=force_update) File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/models/base.py", line 551, in save_base result = manager._insert([self], fields=fields, return_id=update_pk, using=using, raw=raw) File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/models/manager.py", line 203, in _insert return insert_query(self.model, objs, fields, **kwargs) File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/models/query.py", line 1576, in insert_query return query.get_compiler(using=using).execute_sql(return_id) File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 914, in execute_sql return self.connection.ops.fetch_returned_insert_id(cursor) File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/ lib/python2.6/site-packages/django/db/backends/__init__.py", line 529, in fetch_returned_insert_id return cursor.fetchone()[0] TypeError: 'NoneType' object is unsubscriptable
My postgresql table for object is a partioned one, based on a trigger on insert that look for the right child table. I have a hard time finding information about this, except one post here http://postgresql.1045698.n5.nabble.com/INSERT-INTO-RETURNING-with-partitioned-table-based-on-trigger-function-td3307384.html suggesting to use rule instead of triggers for handling insert returning clause (and it seems it really can handle only ONE returning clause, i.e. return object.id). And in any way, what I really don't understand is that everything worked just fine in django 1.3. I don't know this is a real issue or me handling table partitioning the wrong way. Thank you for your help. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.