This stuff is killing me. LOL I think I just don't understand the
urllib2 yet.
I'm trying something very simple, but am having a terrible time
figuring out how to get it to work in python and django. All I want
to do is post to my site with params. Here is what I have:
def test(request):
test = " NOTHING "
if request.method=='POST':
test = request.POST.get('test',None)
print 'data posted'
print 'test param: ',test
return HttpResponse("Text only, please."+str(test),
content_type="text/plain")
Here is how I'm trying to call it via IDLE:
>>> parms = urllib.urlencode([('test','testing'),('test2','testing2')])
>>> print parms
test=testing&test2=testing2
>>> response = urllib2.urlopen('http://my.ip.address:8080/myapp/test/',parms)
Heres the error:
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 124, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 389, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 502, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 427, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 361, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/
python2.6/urllib2.py", line 510, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: FORBIDDEN
Any advice is greatly appreciated. Thanks.
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