On Jan 16, 8:04 am, Arun P <arun....@gmail.com> wrote:
> Does this work?
>
> info =
> ExtraInformation.objects.filter(user__is_active=1,user__is_staff=0,user__is_superuser=0).order_by("popularity").select_related("user")
>
> users = map(lambda i: i.user, info)
That was for the "uselessly complicated and memory-hungry" method. Now
for the "simple lazy" method:
=> users = User.objects.filter(<you filters
here>).order_by("extrainformation__popularity")
@OP : You can add a select_related if you plan on using data from
ExtraInformation so you save on useless queries.
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