I am using generic views to produce a paginated specimen list. In the list, you can click on a specimen to get the generic view detail. After viewing the detail, the user will likely want to go back to the specimen list, on the page where the link came from. Pressing the back button works, but I'd like to give the user a link to take them back. How do I go this?
I tried passing the page number from the generic list view into the generic detail view with a url like: /specimen/244/?page=7. However there does not seem to be any way to access GET data in the template. Since there is no view, it can't be retrieved there and passed to the template. (And in general it seems like it would be nice to pass GET values directly into a template without needing the intervention of a view. Is this possible? Thanks in advance for help. I am new to Django so excuse me if I have missed something obvious.... --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
