On Wed, Oct 26, 2011 at 9:06 PM, Swaroop Shankar V <swaroo...@gmail.com> wrote:
> Hello All,
> Am pretty new to Django. I am trying to create a form which will upload an
> image and then enable the user to crop visually (using JCrop plugin). Am
> not completely sure on how to implement this in Django. I am thinking of
> first saving the uploaded image into the disk as a jpeg file and then load
> and display the image as an overlay where the user can crop the image. I am
> able to create a form with the image field and then am passing over
> request.FILE to a function called handle_uploaded_image. Following is
> my handle_uploaded_image function
> def handle_uploaded_image(self, image):
> """
> This function is to handle uploaded image file
> """
> imageFile = Image.open(StringIO.StringIO(image.read()))
> fileName = hashlib.md5(imageFile.getvalue()).hexdigest()+'.jpg'
> Now i am kind of confused on how to convert the uploaded image into jpg
> using PIL, and then saving into the disk. I had defined a field in my model
> to save the image file name which is as follows:
> class UserProfile(models.Model):
>
> avatar = models.ImageField(_('Avatar'),upload_to=settings.IMAGE_UPLOAD_PATH,
> null=True)
>
> I did this based on the django documentation, but it tells something about
> binding the form which am not able to correctly understand. Why do we need
> to bind a form with image field. Also whats the use of giving upload_to in
> model image field? Thanks in advance for any help.
> Regards,
>
> Swaroop Shankar V
>
http://www.pythonware.com/library/pil/handbook/introduction.htm
The section 'Reading and Writing Images' should make this clear.
Cheers
Tom
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