On Thu, Sep 29, 2011 at 8:36 AM, Felix Wagner <hsaldi...@googlemail.com> wrote:
> Hello,
>
> I'm currently trying to paginate my results from a search query.
>
> views.py:
>
> def search(request):
> query = request.GET.get('q', '')
>
> if query:
> qset = (
> Q(NAME__icontains=query)
> )
> results = Thin_Client.objects.filter(qset).distinct()
>
> else:
> results = []
>
> paginator = Paginator(results, 25)
> try:
> page = int(request.POST.get('page', '1'))
> except ValueError:
> page = 1
> try:
> thin_client = paginator.page(page)
> except (EmptyPage, InvalidPage):
> thin_client = paginator.page(paginator.num_pages)
>
> return render_to_response("thin_clients/thin_client_search.html",
> {
> "results": results,
> "query": query,
> })
>
You need to actually pass the paginated page ('thin_client') to your
template and iterate over that. You are still iterating over the
unpaginated 'results', so unsurprisingly you don't see the pagination.
See the view example in the docs:
https://docs.djangoproject.com/en/1.3/topics/pagination/#using-paginator-in-a-view
Cheers
Tom
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