Dear users, I have simple question which regards with running script from view.py. Part of my view.py looks like: def updateSystem(request): print request.POST id = 20 idgrp = 0 print "ID: %d and IDGRP: %d" % (id, idgrp) if request.is_ajax(): message = "This is AJAX part" if request.method == 'POST': query = request.POST print query.items() try: sysid=51 output = subprocess.Popen(['/home/user/djcode/testlab/ updateSys','-sysid','%d','-id','%d','-idgrp','%d' % (sysid,id,idgrp)], shell = False, stdou=subprocess.PIPE) test,err = output.communicate() print output.returncode print err print test except OSError: return HttpResponse("Wrong command") print "CORRECT REQUEST: %s" % query.get('data','sysid=0') message = "Content-type text/html\n\n" return HttpResponse(message) else: return HttpResponse(status=400) else: message = "This is not AJXA" return HttpResponse(status=400)
Is it possible to do that over subprocess command? >From the command line script updateSys written in Python as well should return list of directory. Thank you best regards Petr -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.