On Tuesday, 13 September 2011 12:40:59 UTC+1, David wrote: > > Hello > > This is my code so far from urls.py > > from django.views.generic import ListView, create_update > > url(r'^reportwriting/types/edit/(?P<object_id>\d+)/?$', > create_update.update_object( > model=Type > )), > > I am trying to use the new CRUD generic views but am repeatedly > getting the following error: > > TypeError at /reportwriting/types/edit/1/ > update_object() takes at least 1 argument (1 given) > > I think syntactically I must be screwing up, but am not having much > progress using the Django docs. > > Thanks for any assistance.
create_update.update_object is one of the *old* function views. They work the same as any other functional view: you don't *call* them in urls.py, you reference them and pass extra context arguments as necessary. The new class-based CRUD views are documented here: https://docs.djangoproject.com/en/1.3/ref/class-based-views/#editing-views You probably want UpdateView, which like all class-based view needs to be referenced in urls.py as UpdateView.as_view(model=Foo) -- DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To view this discussion on the web visit https://groups.google.com/d/msg/django-users/-/wymV24iokYIJ. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
