try this
def get_file_path(instance, filename):
path = 'your upload directory'
extension = filename.split('.')[-1].lower()
new_file_name = self.id
return '%(path)s/%(filename)s.%(extension)s' %
{
'path': path,
'filename':
new_file_name',
'extension':
extension
}
class Decision(m.Model):
...
decision = m.FileField(upload_to=get_file_path)
On Sep 5, 11:01 am, Stratos Moros <s.mo...@indev.gr> wrote:
> I forgot to mention that i have imported models like this:
>
> import django.db.models as m
>
> This should explain the first two lines.
>
>
>
>
>
>
>
> On Mon, Sep 5, 2011 at 12:28 PM, Stratos Moros <s.mo...@indev.gr> wrote:
> > Hello,
>
> > I have a model that includes a FileField. When the user uploads a file
> > via the admin interface, I want the file to be saved as 'upload_to/
> > primary_key/original_filename'. Since the object will not be saved in
> > the database when the user uploads the file, it will not have a
> > primary key at that point. This is my workaround:
>
> > class Decision(m.Model):
> > ...
> > decision = m.FileField(upload_to='base_dir/')
> > ...
>
> > def save(self, *args, **kwargs):
> > """ custom save to use pk on filename """
> > #save once to get a pk
> > super(Decision, self).save(*args, **kwargs)
>
> > #get info about the file
> > uploaded = self.decision
> > old_path = self.decision.name
> > basedir, filename = os.path.split(old_path)
> > new_path = os.path.join(basedir, str(self.pk), filename)
>
> > #create the new file, delete the one django created
> > uploaded.storage.save(new_path, uploaded)
> > uploaded.storage.delete(old_path)
>
> > #assign new path and save again
> > self.decision = new_path
> > super(Decision, self).save(*args, **kwargs)
>
> > This works, but seems to be a bit on the hacky side. Basically, I'm
> > letting FileField upload the file to the 'upload_to' path and then
> > move it to its correct path when the object has a primary key.
>
> > I was wondering if there is a better way to do this. Are there any
> > cases where my code wouldn't work?
>
> > Thanks.
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