consider this: findit = inventory.objects.filter(Barcode = self.Barcode, Condition__name = "good")
How could i make this filter say "good" or "acceptable" or IN ('good','acceptable') -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.