Yes that works, thank you. I've submitted a bug report here https://code.djangoproject.com/ticket/16135 The bug is that Parent.objects.filter(child__isnull=False) is not giving the result I expect.
On Jun 1, 10:40 am, Matías Aguirre <matiasagui...@gmail.com> wrote: > This worked on on Django 1.2.5: > > Parent.objects.exclude(child__isnull=True) > > Does it work for you? > > Excerpts from robin's message of Tue May 31 05:53:26 -0300 2011: > > > > > Example code: > > > class Parent(models.Model): > > name = models.CharField(max_length='20',blank=True) > > > class Child(Parent): > > pass > > > I want to get the result of Child.objects.all() but I DO NOT want to > > use Child. > > I want to use Parent instead, which I tried to do with: > > > Parent.objects.filter(child__isnull=False) > > > Which doesn't work and gives the result of Product.objects.all() > > instead. > > However If I do the following, it WORKS: > > > Parent.objects.filter(child__name__isnull=False) > > > Another way, if I insist on using > > Parent.objects.filter(child__isnull=False), is to change the Child > > model to the following: > > > class Child(models.Model): > > parent = models.OneToOneField(Parent) > > > Then Parent.objects.filter(child__isnull=False) would WORK > > > The problem with the 2 solutions above is that filtering with > > child__name__isnull looks hackish, and I don't want to change my Child > > model to use OneToOneField. > > > So is there a better way? > > > Thanks, > > Robin > > -- > Matías Aguirre <matiasagui...@gmail.com> -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.