On Tuesday, May 24, 2011 11:13:31 AM UTC+1, Lloyd Dube wrote:
>
> Hi Everyone,
>
> I am trying to parse an XML feed and display the text of each child node
> without any success. My code in the python shell is as follows:
>
> >>>import urllib
> >>>from xml.etree import ElementTree as ET
>
> >>>content = urllib.urlopen('
> http://xml.matchbook.com/xmlfeed/feed?sport-id=&vendor=TEST&sport-name=&short-name=Po
> ')
> >>>xml_content = ET.parse(content)
>
> I then check the xml_content object as follows:
>
> >>>xml_content
> <xml.etree.ElementTree.ElementTree instance at 0x01DC14B8>
>
> And now, to iterate through its child nodes and print out the text of each
> node:
>
> >>>for node in xml_content.getiterator('contest'):
> ... name = node.attrib.get('text')
> ... print name
> ...
> >>>
>
> Nothing is printed, even though the document does have 'contest' tags with
> text in them. If I try to count the contest tags and increment an integer
> (to see that the document is traversed) I get the same result - the int
> remains at 0.
>
> >>> i = 0
> >>> for node in xml_content.getiterator('contest'):
> ... i += 1
> ...
> >>> i
> 0
>
> What am I getting wrong? Any hints would be appreciated.
>
> --
> Regards,
> Sithembewena Lloyd Dube
This isn't really a Django question...
Nevertheless, the issue is probably in the line "name =
node.attrib.get('text')". What this does is get the attribute of the current
node that has the name 'text' - ie if your XML was like this:
<contest text="foo"/>
However, what you probably have is this:
<contest>foo</contest>
in which case you just want to access the `text` property directly:
name = node.text
--
DR.
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