On Thu, Mar 24, 2011 at 12:40 PM, Ryan Osborn <ryan.osbor...@gmail.com> wrote: > I was just wondering if there was a simple way to condense this as > with django 1.2 I could add all this in to a dictionary like: > > info_dict = {'model': Entry, 'date_field': 'created', 'paginate_by': > 10}
Can you not set your info_dict just like that, and then rewrite it like this: YearArchiveView.as_view(**info_dict),name='blog_archive_year'), url(r'(?P<year>\d{4})/(?P<month>[a-z]{3})/$', -- Regards, Ian Clelland <clell...@gmail.com> -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.