this seems to work:

results = sorted(results, key=lambda x: x.user.last_login,
reverse=True)

I dont understand what the x is, but thank you so much for fixing this
for me in a matter of minutes!

On Feb 11, 8:36 pm, Shawn Milochik <sh...@milochik.com> wrote:
> Something like this:
>
> key = lambda x: x.last_login

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