On Tue, Feb 8, 2011 at 6:00 PM, Andres Lucena <andresluc...@gmail.com> wrote:
> Dear Gurus,
>
> I've made a custom method for getting the score (from django-voting)
> for a giving Model:
>
> class Link(models.Model):
> episode = models.ForeignKey("Episode", related_name="links")
> url = models.CharField(max_length=255, unique=True, db_index=True)
>
> def __unicode__(self):
> return self.url
>
> def get_score(self):
> return Vote.objects.get_score(self)['score']
>
> Now I want to make a custom manager to getting the top-scored links
> for the given episode. AFAIK, you can't sort by a custom method, so
> I'm trying to apply the ordering through sorted(), like this links
> says:
>
> http://stackoverflow.com/questions/981375/using-a-django-custom-model-method-property-in-order-by
> http://stackoverflow.com/questions/883575/custom-ordering-in-django
>
> So, what I have now is this:
>
> class LinkGetTopScores(models.Manager):
> def get_top_score(self):
> return sorted(self.filter(episode=self.episode), key=lambda n:
> n.get_score)
>
> class Link(models.Model):
> episode = models.ForeignKey("Episode", related_name="links")
> url = models.CharField(max_length=255, unique=True, db_index=True)
> get_top_score = LinkGetTopScores()
> ....
>
> So of course this isn't working because of the self.episode stuff...
> But I've to filter somehow by episode (the ForeignKey), and I don't
> know how. Is there anyway of doing this?? What I'm doing is right or
> there would be an easier way of doing this?
>
I noticed that the .filter isn't necesary, so now I have this:
class LinkGetTopScores(models.Manager):
def get_top_score(self):
return sorted(self.all(), key=lambda n: n.get_score)
But it don't sort by score, and I don't know what I'm doing wrong :S
Any idea?
Thanks,
Andres
> Thank you,
> Andres
>
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