I was able to find the solution to it myself.
The key was to
1. Create a custom field that extended ModelChoiceField.
2. Overwrite the label_from_instance method in the custom field.
3. Return a HTML string from the label_from_instance method, and
marking that as a safe_string.
from django.forms import ModelChoiceField
from django.utils.safestring import mark_safe
class ThemeChoiceField(ModelChoiceField):
def label_from_instance(self,obj):
return mark_safe("%s - Click <a target='_other' rel='#theme_
%s' class='overlay_trigger'>here</a> to see an example. \
<div class='simple_overlay' id='theme_%s'><img src='%s'></
img></div> " \
% (obj.name, obj.pk, obj.pk, obj.image.url))
-Adi
On Dec 30 2010, 6:36 pm, Adi <aditya.rus...@gmail.com> wrote:
> Hi I have a situation like this
>
> class AppearanceThemesForm(forms.Form):
> page_theme =
> forms.ModelChoiceField(widget=forms.RadioSelect(attrs={'title':'Select
> the appropriate theme for your pages.'}),
>
> queryset=Theme.objects.filter(section="1"),
>
> initial=Theme.objects.get(section="1",representation="").pk,
> label="Page Theme")
>
> And my Theme model is like this:
>
> class Theme(models.Model):
> name = models.CharField(max_length=32)
> image = models.ImageField(upload_to="images/themes", null=True)
>
> def __unicode__(self):
> return "%s" % (self.name)
>
> When I render AppearanceThemesForm in my template, i would like to be
> able to show a link next to the label. If a user clicks the link, the
> webpage displays the image associated with Theme.
>
> I tried putting in a custom field that extends the ModelChoiceField,
> and in the label_from_instance method, tried to output the HTML, but
> that gets escaped.
>
> What is the proper way to achieve what i am trying to do?
>
> Alternatively, how do i get access the underlying model object behind
> the modelchoice field in my templates?
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